Integrand size = 15, antiderivative size = 217 \[ \int \left (a+b \sqrt [3]{x}\right )^{15} x^5 \, dx=\frac {a^{15} x^6}{6}+\frac {45}{19} a^{14} b x^{19/3}+\frac {63}{4} a^{13} b^2 x^{20/3}+65 a^{12} b^3 x^7+\frac {4095}{22} a^{11} b^4 x^{22/3}+\frac {9009}{23} a^{10} b^5 x^{23/3}+\frac {5005}{8} a^9 b^6 x^8+\frac {3861}{5} a^8 b^7 x^{25/3}+\frac {1485}{2} a^7 b^8 x^{26/3}+\frac {5005}{9} a^6 b^9 x^9+\frac {1287}{4} a^5 b^{10} x^{28/3}+\frac {4095}{29} a^4 b^{11} x^{29/3}+\frac {91}{2} a^3 b^{12} x^{10}+\frac {315}{31} a^2 b^{13} x^{31/3}+\frac {45}{32} a b^{14} x^{32/3}+\frac {b^{15} x^{11}}{11} \]
1/6*a^15*x^6+45/19*a^14*b*x^(19/3)+63/4*a^13*b^2*x^(20/3)+65*a^12*b^3*x^7+ 4095/22*a^11*b^4*x^(22/3)+9009/23*a^10*b^5*x^(23/3)+5005/8*a^9*b^6*x^8+386 1/5*a^8*b^7*x^(25/3)+1485/2*a^7*b^8*x^(26/3)+5005/9*a^6*b^9*x^9+1287/4*a^5 *b^10*x^(28/3)+4095/29*a^4*b^11*x^(29/3)+91/2*a^3*b^12*x^10+315/31*a^2*b^1 3*x^(31/3)+45/32*a*b^14*x^(32/3)+1/11*b^15*x^11
Time = 0.05 (sec) , antiderivative size = 191, normalized size of antiderivative = 0.88 \[ \int \left (a+b \sqrt [3]{x}\right )^{15} x^5 \, dx=\frac {1037158320 a^{15} x^6+14738565600 a^{14} b x^{19/3}+98011461240 a^{13} b^2 x^{20/3}+404491744800 a^{12} b^3 x^7+1158317269200 a^{11} b^4 x^{22/3}+2437502427360 a^{10} b^5 x^{23/3}+3893233043700 a^9 b^6 x^8+4805361928224 a^8 b^7 x^{25/3}+4620540315600 a^7 b^8 x^{26/3}+3460651594400 a^6 b^9 x^9+2002234136760 a^5 b^{10} x^{28/3}+878723445600 a^4 b^{11} x^{29/3}+283144221360 a^3 b^{12} x^{10}+63233200800 a^2 b^{13} x^{31/3}+8751023325 a b^{14} x^{32/3}+565722720 b^{15} x^{11}}{6222949920} \]
(1037158320*a^15*x^6 + 14738565600*a^14*b*x^(19/3) + 98011461240*a^13*b^2* x^(20/3) + 404491744800*a^12*b^3*x^7 + 1158317269200*a^11*b^4*x^(22/3) + 2 437502427360*a^10*b^5*x^(23/3) + 3893233043700*a^9*b^6*x^8 + 4805361928224 *a^8*b^7*x^(25/3) + 4620540315600*a^7*b^8*x^(26/3) + 3460651594400*a^6*b^9 *x^9 + 2002234136760*a^5*b^10*x^(28/3) + 878723445600*a^4*b^11*x^(29/3) + 283144221360*a^3*b^12*x^10 + 63233200800*a^2*b^13*x^(31/3) + 8751023325*a* b^14*x^(32/3) + 565722720*b^15*x^11)/6222949920
Time = 0.37 (sec) , antiderivative size = 221, normalized size of antiderivative = 1.02, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.200, Rules used = {798, 49, 2009}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
| \(\displaystyle \int x^5 \left (a+b \sqrt [3]{x}\right )^{15} \, dx\) |
| \(\Big \downarrow \) 798 |
| \(\displaystyle 3 \int \left (a+b \sqrt [3]{x}\right )^{15} x^{17/3}d\sqrt [3]{x}\) |
| \(\Big \downarrow \) 49 |
| \(\displaystyle 3 \int \left (x^{17/3} a^{15}+15 b x^6 a^{14}+105 b^2 x^{19/3} a^{13}+455 b^3 x^{20/3} a^{12}+1365 b^4 x^7 a^{11}+3003 b^5 x^{22/3} a^{10}+5005 b^6 x^{23/3} a^9+6435 b^7 x^8 a^8+6435 b^8 x^{25/3} a^7+5005 b^9 x^{26/3} a^6+3003 b^{10} x^9 a^5+1365 b^{11} x^{28/3} a^4+455 b^{12} x^{29/3} a^3+105 b^{13} x^{10} a^2+15 b^{14} x^{31/3} a+b^{15} x^{32/3}\right )d\sqrt [3]{x}\) |
| \(\Big \downarrow \) 2009 |
| \(\displaystyle 3 \left (\frac {a^{15} x^6}{18}+\frac {15}{19} a^{14} b x^{19/3}+\frac {21}{4} a^{13} b^2 x^{20/3}+\frac {65}{3} a^{12} b^3 x^7+\frac {1365}{22} a^{11} b^4 x^{22/3}+\frac {3003}{23} a^{10} b^5 x^{23/3}+\frac {5005}{24} a^9 b^6 x^8+\frac {1287}{5} a^8 b^7 x^{25/3}+\frac {495}{2} a^7 b^8 x^{26/3}+\frac {5005}{27} a^6 b^9 x^9+\frac {429}{4} a^5 b^{10} x^{28/3}+\frac {1365}{29} a^4 b^{11} x^{29/3}+\frac {91}{6} a^3 b^{12} x^{10}+\frac {105}{31} a^2 b^{13} x^{31/3}+\frac {15}{32} a b^{14} x^{32/3}+\frac {b^{15} x^{11}}{33}\right )\) |
3*((a^15*x^6)/18 + (15*a^14*b*x^(19/3))/19 + (21*a^13*b^2*x^(20/3))/4 + (6 5*a^12*b^3*x^7)/3 + (1365*a^11*b^4*x^(22/3))/22 + (3003*a^10*b^5*x^(23/3)) /23 + (5005*a^9*b^6*x^8)/24 + (1287*a^8*b^7*x^(25/3))/5 + (495*a^7*b^8*x^( 26/3))/2 + (5005*a^6*b^9*x^9)/27 + (429*a^5*b^10*x^(28/3))/4 + (1365*a^4*b ^11*x^(29/3))/29 + (91*a^3*b^12*x^10)/6 + (105*a^2*b^13*x^(31/3))/31 + (15 *a*b^14*x^(32/3))/32 + (b^15*x^11)/33)
3.24.39.3.1 Defintions of rubi rules used
Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int [ExpandIntegrand[(a + b*x)^m*(c + d*x)^n, x], x] /; FreeQ[{a, b, c, d}, x] && IGtQ[m, 0] && IGtQ[m + n + 2, 0]
Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[1/n Subst [Int[x^(Simplify[(m + 1)/n] - 1)*(a + b*x)^p, x], x, x^n], x] /; FreeQ[{a, b, m, n, p}, x] && IntegerQ[Simplify[(m + 1)/n]]
Time = 3.44 (sec) , antiderivative size = 168, normalized size of antiderivative = 0.77
| method | result | size |
| derivativedivides | \(\frac {a^{15} x^{6}}{6}+\frac {45 a^{14} b \,x^{\frac {19}{3}}}{19}+\frac {63 a^{13} b^{2} x^{\frac {20}{3}}}{4}+65 a^{12} b^{3} x^{7}+\frac {4095 a^{11} b^{4} x^{\frac {22}{3}}}{22}+\frac {9009 a^{10} b^{5} x^{\frac {23}{3}}}{23}+\frac {5005 a^{9} b^{6} x^{8}}{8}+\frac {3861 a^{8} b^{7} x^{\frac {25}{3}}}{5}+\frac {1485 a^{7} b^{8} x^{\frac {26}{3}}}{2}+\frac {5005 a^{6} b^{9} x^{9}}{9}+\frac {1287 a^{5} b^{10} x^{\frac {28}{3}}}{4}+\frac {4095 a^{4} b^{11} x^{\frac {29}{3}}}{29}+\frac {91 a^{3} b^{12} x^{10}}{2}+\frac {315 a^{2} b^{13} x^{\frac {31}{3}}}{31}+\frac {45 a \,b^{14} x^{\frac {32}{3}}}{32}+\frac {b^{15} x^{11}}{11}\) | \(168\) |
| default | \(\frac {a^{15} x^{6}}{6}+\frac {45 a^{14} b \,x^{\frac {19}{3}}}{19}+\frac {63 a^{13} b^{2} x^{\frac {20}{3}}}{4}+65 a^{12} b^{3} x^{7}+\frac {4095 a^{11} b^{4} x^{\frac {22}{3}}}{22}+\frac {9009 a^{10} b^{5} x^{\frac {23}{3}}}{23}+\frac {5005 a^{9} b^{6} x^{8}}{8}+\frac {3861 a^{8} b^{7} x^{\frac {25}{3}}}{5}+\frac {1485 a^{7} b^{8} x^{\frac {26}{3}}}{2}+\frac {5005 a^{6} b^{9} x^{9}}{9}+\frac {1287 a^{5} b^{10} x^{\frac {28}{3}}}{4}+\frac {4095 a^{4} b^{11} x^{\frac {29}{3}}}{29}+\frac {91 a^{3} b^{12} x^{10}}{2}+\frac {315 a^{2} b^{13} x^{\frac {31}{3}}}{31}+\frac {45 a \,b^{14} x^{\frac {32}{3}}}{32}+\frac {b^{15} x^{11}}{11}\) | \(168\) |
| trager | \(\frac {\left (72 b^{15} x^{10}+36036 a^{3} b^{12} x^{9}+72 b^{15} x^{9}+440440 a^{6} b^{9} x^{8}+36036 a^{3} b^{12} x^{8}+72 b^{15} x^{8}+495495 a^{9} b^{6} x^{7}+440440 a^{6} b^{9} x^{7}+36036 a^{3} b^{12} x^{7}+72 b^{15} x^{7}+51480 a^{12} b^{3} x^{6}+495495 a^{9} b^{6} x^{6}+440440 a^{6} b^{9} x^{6}+36036 a^{3} b^{12} x^{6}+72 b^{15} x^{6}+132 a^{15} x^{5}+51480 a^{12} b^{3} x^{5}+495495 a^{9} b^{6} x^{5}+440440 a^{6} b^{9} x^{5}+36036 a^{3} b^{12} x^{5}+72 b^{15} x^{5}+132 x^{4} a^{15}+51480 a^{12} b^{3} x^{4}+495495 a^{9} b^{6} x^{4}+440440 a^{6} b^{9} x^{4}+36036 a^{3} b^{12} x^{4}+72 b^{15} x^{4}+132 x^{3} a^{15}+51480 a^{12} b^{3} x^{3}+495495 a^{9} b^{6} x^{3}+440440 a^{6} b^{9} x^{3}+36036 a^{3} b^{12} x^{3}+72 b^{15} x^{3}+132 x^{2} a^{15}+51480 a^{12} b^{3} x^{2}+495495 a^{9} b^{6} x^{2}+440440 a^{6} b^{9} x^{2}+36036 a^{3} b^{12} x^{2}+72 b^{15} x^{2}+132 x \,a^{15}+51480 a^{12} b^{3} x +495495 a^{9} b^{6} x +440440 a^{6} b^{9} x +36036 a^{3} b^{12} x +72 b^{15} x +132 a^{15}+51480 a^{12} b^{3}+495495 a^{9} b^{6}+440440 a^{6} b^{9}+36036 a^{3} b^{12}+72 b^{15}\right ) \left (-1+x \right )}{792}+\frac {9 a^{2} b \,x^{\frac {19}{3}} \left (146300 b^{12} x^{4}+4632485 a^{3} b^{9} x^{3}+11117964 a^{6} b^{6} x^{2}+2679950 a^{9} b^{3} x +34100 a^{12}\right )}{129580}+\frac {9 a \,b^{2} x^{\frac {20}{3}} \left (3335 b^{12} x^{4}+334880 a^{3} b^{9} x^{3}+1760880 a^{6} b^{6} x^{2}+928928 a^{9} b^{3} x +37352 a^{12}\right )}{21344}\) | \(596\) |
1/6*a^15*x^6+45/19*a^14*b*x^(19/3)+63/4*a^13*b^2*x^(20/3)+65*a^12*b^3*x^7+ 4095/22*a^11*b^4*x^(22/3)+9009/23*a^10*b^5*x^(23/3)+5005/8*a^9*b^6*x^8+386 1/5*a^8*b^7*x^(25/3)+1485/2*a^7*b^8*x^(26/3)+5005/9*a^6*b^9*x^9+1287/4*a^5 *b^10*x^(28/3)+4095/29*a^4*b^11*x^(29/3)+91/2*a^3*b^12*x^10+315/31*a^2*b^1 3*x^(31/3)+45/32*a*b^14*x^(32/3)+1/11*b^15*x^11
Time = 0.27 (sec) , antiderivative size = 179, normalized size of antiderivative = 0.82 \[ \int \left (a+b \sqrt [3]{x}\right )^{15} x^5 \, dx=\frac {1}{11} \, b^{15} x^{11} + \frac {91}{2} \, a^{3} b^{12} x^{10} + \frac {5005}{9} \, a^{6} b^{9} x^{9} + \frac {5005}{8} \, a^{9} b^{6} x^{8} + 65 \, a^{12} b^{3} x^{7} + \frac {1}{6} \, a^{15} x^{6} + \frac {9}{21344} \, {\left (3335 \, a b^{14} x^{10} + 334880 \, a^{4} b^{11} x^{9} + 1760880 \, a^{7} b^{8} x^{8} + 928928 \, a^{10} b^{5} x^{7} + 37352 \, a^{13} b^{2} x^{6}\right )} x^{\frac {2}{3}} + \frac {9}{129580} \, {\left (146300 \, a^{2} b^{13} x^{10} + 4632485 \, a^{5} b^{10} x^{9} + 11117964 \, a^{8} b^{7} x^{8} + 2679950 \, a^{11} b^{4} x^{7} + 34100 \, a^{14} b x^{6}\right )} x^{\frac {1}{3}} \]
1/11*b^15*x^11 + 91/2*a^3*b^12*x^10 + 5005/9*a^6*b^9*x^9 + 5005/8*a^9*b^6* x^8 + 65*a^12*b^3*x^7 + 1/6*a^15*x^6 + 9/21344*(3335*a*b^14*x^10 + 334880* a^4*b^11*x^9 + 1760880*a^7*b^8*x^8 + 928928*a^10*b^5*x^7 + 37352*a^13*b^2* x^6)*x^(2/3) + 9/129580*(146300*a^2*b^13*x^10 + 4632485*a^5*b^10*x^9 + 111 17964*a^8*b^7*x^8 + 2679950*a^11*b^4*x^7 + 34100*a^14*b*x^6)*x^(1/3)
Time = 1.69 (sec) , antiderivative size = 218, normalized size of antiderivative = 1.00 \[ \int \left (a+b \sqrt [3]{x}\right )^{15} x^5 \, dx=\frac {a^{15} x^{6}}{6} + \frac {45 a^{14} b x^{\frac {19}{3}}}{19} + \frac {63 a^{13} b^{2} x^{\frac {20}{3}}}{4} + 65 a^{12} b^{3} x^{7} + \frac {4095 a^{11} b^{4} x^{\frac {22}{3}}}{22} + \frac {9009 a^{10} b^{5} x^{\frac {23}{3}}}{23} + \frac {5005 a^{9} b^{6} x^{8}}{8} + \frac {3861 a^{8} b^{7} x^{\frac {25}{3}}}{5} + \frac {1485 a^{7} b^{8} x^{\frac {26}{3}}}{2} + \frac {5005 a^{6} b^{9} x^{9}}{9} + \frac {1287 a^{5} b^{10} x^{\frac {28}{3}}}{4} + \frac {4095 a^{4} b^{11} x^{\frac {29}{3}}}{29} + \frac {91 a^{3} b^{12} x^{10}}{2} + \frac {315 a^{2} b^{13} x^{\frac {31}{3}}}{31} + \frac {45 a b^{14} x^{\frac {32}{3}}}{32} + \frac {b^{15} x^{11}}{11} \]
a**15*x**6/6 + 45*a**14*b*x**(19/3)/19 + 63*a**13*b**2*x**(20/3)/4 + 65*a* *12*b**3*x**7 + 4095*a**11*b**4*x**(22/3)/22 + 9009*a**10*b**5*x**(23/3)/2 3 + 5005*a**9*b**6*x**8/8 + 3861*a**8*b**7*x**(25/3)/5 + 1485*a**7*b**8*x* *(26/3)/2 + 5005*a**6*b**9*x**9/9 + 1287*a**5*b**10*x**(28/3)/4 + 4095*a** 4*b**11*x**(29/3)/29 + 91*a**3*b**12*x**10/2 + 315*a**2*b**13*x**(31/3)/31 + 45*a*b**14*x**(32/3)/32 + b**15*x**11/11
Time = 0.21 (sec) , antiderivative size = 302, normalized size of antiderivative = 1.39 \[ \int \left (a+b \sqrt [3]{x}\right )^{15} x^5 \, dx=\frac {{\left (b x^{\frac {1}{3}} + a\right )}^{33}}{11 \, b^{18}} - \frac {51 \, {\left (b x^{\frac {1}{3}} + a\right )}^{32} a}{32 \, b^{18}} + \frac {408 \, {\left (b x^{\frac {1}{3}} + a\right )}^{31} a^{2}}{31 \, b^{18}} - \frac {68 \, {\left (b x^{\frac {1}{3}} + a\right )}^{30} a^{3}}{b^{18}} + \frac {7140 \, {\left (b x^{\frac {1}{3}} + a\right )}^{29} a^{4}}{29 \, b^{18}} - \frac {663 \, {\left (b x^{\frac {1}{3}} + a\right )}^{28} a^{5}}{b^{18}} + \frac {12376 \, {\left (b x^{\frac {1}{3}} + a\right )}^{27} a^{6}}{9 \, b^{18}} - \frac {2244 \, {\left (b x^{\frac {1}{3}} + a\right )}^{26} a^{7}}{b^{18}} + \frac {14586 \, {\left (b x^{\frac {1}{3}} + a\right )}^{25} a^{8}}{5 \, b^{18}} - \frac {12155 \, {\left (b x^{\frac {1}{3}} + a\right )}^{24} a^{9}}{4 \, b^{18}} + \frac {58344 \, {\left (b x^{\frac {1}{3}} + a\right )}^{23} a^{10}}{23 \, b^{18}} - \frac {18564 \, {\left (b x^{\frac {1}{3}} + a\right )}^{22} a^{11}}{11 \, b^{18}} + \frac {884 \, {\left (b x^{\frac {1}{3}} + a\right )}^{21} a^{12}}{b^{18}} - \frac {357 \, {\left (b x^{\frac {1}{3}} + a\right )}^{20} a^{13}}{b^{18}} + \frac {2040 \, {\left (b x^{\frac {1}{3}} + a\right )}^{19} a^{14}}{19 \, b^{18}} - \frac {68 \, {\left (b x^{\frac {1}{3}} + a\right )}^{18} a^{15}}{3 \, b^{18}} + \frac {3 \, {\left (b x^{\frac {1}{3}} + a\right )}^{17} a^{16}}{b^{18}} - \frac {3 \, {\left (b x^{\frac {1}{3}} + a\right )}^{16} a^{17}}{16 \, b^{18}} \]
1/11*(b*x^(1/3) + a)^33/b^18 - 51/32*(b*x^(1/3) + a)^32*a/b^18 + 408/31*(b *x^(1/3) + a)^31*a^2/b^18 - 68*(b*x^(1/3) + a)^30*a^3/b^18 + 7140/29*(b*x^ (1/3) + a)^29*a^4/b^18 - 663*(b*x^(1/3) + a)^28*a^5/b^18 + 12376/9*(b*x^(1 /3) + a)^27*a^6/b^18 - 2244*(b*x^(1/3) + a)^26*a^7/b^18 + 14586/5*(b*x^(1/ 3) + a)^25*a^8/b^18 - 12155/4*(b*x^(1/3) + a)^24*a^9/b^18 + 58344/23*(b*x^ (1/3) + a)^23*a^10/b^18 - 18564/11*(b*x^(1/3) + a)^22*a^11/b^18 + 884*(b*x ^(1/3) + a)^21*a^12/b^18 - 357*(b*x^(1/3) + a)^20*a^13/b^18 + 2040/19*(b*x ^(1/3) + a)^19*a^14/b^18 - 68/3*(b*x^(1/3) + a)^18*a^15/b^18 + 3*(b*x^(1/3 ) + a)^17*a^16/b^18 - 3/16*(b*x^(1/3) + a)^16*a^17/b^18
Time = 0.26 (sec) , antiderivative size = 167, normalized size of antiderivative = 0.77 \[ \int \left (a+b \sqrt [3]{x}\right )^{15} x^5 \, dx=\frac {1}{11} \, b^{15} x^{11} + \frac {45}{32} \, a b^{14} x^{\frac {32}{3}} + \frac {315}{31} \, a^{2} b^{13} x^{\frac {31}{3}} + \frac {91}{2} \, a^{3} b^{12} x^{10} + \frac {4095}{29} \, a^{4} b^{11} x^{\frac {29}{3}} + \frac {1287}{4} \, a^{5} b^{10} x^{\frac {28}{3}} + \frac {5005}{9} \, a^{6} b^{9} x^{9} + \frac {1485}{2} \, a^{7} b^{8} x^{\frac {26}{3}} + \frac {3861}{5} \, a^{8} b^{7} x^{\frac {25}{3}} + \frac {5005}{8} \, a^{9} b^{6} x^{8} + \frac {9009}{23} \, a^{10} b^{5} x^{\frac {23}{3}} + \frac {4095}{22} \, a^{11} b^{4} x^{\frac {22}{3}} + 65 \, a^{12} b^{3} x^{7} + \frac {63}{4} \, a^{13} b^{2} x^{\frac {20}{3}} + \frac {45}{19} \, a^{14} b x^{\frac {19}{3}} + \frac {1}{6} \, a^{15} x^{6} \]
1/11*b^15*x^11 + 45/32*a*b^14*x^(32/3) + 315/31*a^2*b^13*x^(31/3) + 91/2*a ^3*b^12*x^10 + 4095/29*a^4*b^11*x^(29/3) + 1287/4*a^5*b^10*x^(28/3) + 5005 /9*a^6*b^9*x^9 + 1485/2*a^7*b^8*x^(26/3) + 3861/5*a^8*b^7*x^(25/3) + 5005/ 8*a^9*b^6*x^8 + 9009/23*a^10*b^5*x^(23/3) + 4095/22*a^11*b^4*x^(22/3) + 65 *a^12*b^3*x^7 + 63/4*a^13*b^2*x^(20/3) + 45/19*a^14*b*x^(19/3) + 1/6*a^15* x^6
Time = 0.18 (sec) , antiderivative size = 167, normalized size of antiderivative = 0.77 \[ \int \left (a+b \sqrt [3]{x}\right )^{15} x^5 \, dx=\frac {a^{15}\,x^6}{6}+\frac {b^{15}\,x^{11}}{11}+\frac {45\,a^{14}\,b\,x^{19/3}}{19}+\frac {45\,a\,b^{14}\,x^{32/3}}{32}+65\,a^{12}\,b^3\,x^7+\frac {5005\,a^9\,b^6\,x^8}{8}+\frac {5005\,a^6\,b^9\,x^9}{9}+\frac {91\,a^3\,b^{12}\,x^{10}}{2}+\frac {63\,a^{13}\,b^2\,x^{20/3}}{4}+\frac {4095\,a^{11}\,b^4\,x^{22/3}}{22}+\frac {9009\,a^{10}\,b^5\,x^{23/3}}{23}+\frac {3861\,a^8\,b^7\,x^{25/3}}{5}+\frac {1485\,a^7\,b^8\,x^{26/3}}{2}+\frac {1287\,a^5\,b^{10}\,x^{28/3}}{4}+\frac {4095\,a^4\,b^{11}\,x^{29/3}}{29}+\frac {315\,a^2\,b^{13}\,x^{31/3}}{31} \]
(a^15*x^6)/6 + (b^15*x^11)/11 + (45*a^14*b*x^(19/3))/19 + (45*a*b^14*x^(32 /3))/32 + 65*a^12*b^3*x^7 + (5005*a^9*b^6*x^8)/8 + (5005*a^6*b^9*x^9)/9 + (91*a^3*b^12*x^10)/2 + (63*a^13*b^2*x^(20/3))/4 + (4095*a^11*b^4*x^(22/3)) /22 + (9009*a^10*b^5*x^(23/3))/23 + (3861*a^8*b^7*x^(25/3))/5 + (1485*a^7* b^8*x^(26/3))/2 + (1287*a^5*b^10*x^(28/3))/4 + (4095*a^4*b^11*x^(29/3))/29 + (315*a^2*b^13*x^(31/3))/31